A^2-b^2=2

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Solution for A^2-b^2=2 equation: 



^2-A^2=2

We move all terms to the left:

^2-A^2-(2)=0

determiningTheFunctionDomain
-A^2-2+^2=0

We add all the numbers together, and all the variables

-1A^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-2}=0$

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